
Arturo O. answered 05/05/18
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(A)
Assuming the concentration doubles every T hours,
C(t) = C0 (2)t/T
t = hours
T = doubling period
C0 = initial concentration = 50,000 bacteria per ml
(B)
T = 4 hours
375,0000 = 50,000 (2)t/4
7.5 = 2t/4
log7.5 = (t/4)log2
t = 4 log7.5 / log2 ≅ 11.63 hours
(C)
C(24) = 50,000 (2)24/4 = ? bacteria per ml
You can finish from here.