You don't specifically say, but I think the problem means candies drawn WITHOUT replacement.
The probability is: (4/13) * (3/12) * (2/11) = 24/(13*12*11) = 2/143.
Sayra G.
asked • 04/27/18A bag of candy contains 9 peppermints and 4 butterscotch candies. What is the probability that 3 randomly drawn candies will all be butterscotch?
A bag of candy contains 9 peppermints and 4 butterscotch candies.
What is the probability that 3 randomly drawn candies will all be butterscotch?
What is the probability that 3 randomly drawn candies will all be butterscotch?
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