Mark B. answered 04/23/18
Tutor
New to Wyzant
PhD Candidate in Psychology: Experienced Math, Statistics, Tutor
Good morning, Chloe,
Originally, I would have expressed the two numbers you are seeking as x and y. However, since we are told in the problem the following: "The larger number is twice the smaller number," i believe it safe to say that x can be used to express the one number as x and the other as 2x as this expression makes the two numbers different. With that outlined we can now solve our problem.
X + 2X = 18 <-----The sum of two numbers is 18.
Originally, I would have expressed the two numbers you are seeking as x and y. However, since we are told in the problem the following: "The larger number is twice the smaller number," i believe it safe to say that x can be used to express the one number as x and the other as 2x as this expression makes the two numbers different. With that outlined we can now solve our problem.
X + 2X = 18 <-----The sum of two numbers is 18.
Then, we know with certainty, that the expression 2X to be the larger number.
Therefore:
x + 2x = 18
Solve:
3x = 18
x = 6
Now. substitute by plugging in value of x into equation:
6 + 2(6) = 18
Does this proof? Indeed, it does.
6 + 12 =18
18=18
Therefore, your two numbers are 6 and 12.
Please note: Had you assigned x and y as the expressions of your two numbers, this is what would have occurred:
x + y + 18
Solving for y would be as follows:
y = 18 -x
Substituting you would have arrived at:
x + 18 - x = 18
You will notice that your x value would have cancelled leaving you with:
18 = 18
While the above is true, you would have been no closer to determining the value of either x or y.
I hope this answer helped you and that you also have a great week. Please let me know should you have further questions or leave feedback in the comment sectio below.
You will notice that your x value would have cancelled leaving you with:
18 = 18
While the above is true, you would have been no closer to determining the value of either x or y.
I hope this answer helped you and that you also have a great week. Please let me know should you have further questions or leave feedback in the comment sectio below.