David W. answered 04/13/18
Tutor
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(90)
Experienced Prof
Reword the question:
Q: "A dour-digit combination is composed of: (3,4) then (7,8) then (3,4) then (7,8). What are possibilities?
A: Since the four digits are independent (and may be repeated), there are 2*2*2*2 =16 possibilities. They are:
digits count in binary Hexadecimal digit
------- ---------------- ------------------
3 7 3 7 0 0 0 0 0
3 7 3 8 0 0 0 1 1
3 7 4 7 0 0 1 0 2
3 7 4 8 0 0 1 1 3
3 8 3 7 0 1 0 0 4
3 8 3 8 0 1 0 1 5
3 8 4 7 0 1 1 0 6
3 8 4 8 0 1 1 1 7
4 7 3 7 1 0 0 0 8
4 7 3 8 1 0 0 1 9
4 7 4 7 1 0 1 0 A
4 7 4 8 1 0 1 1 B
4 8 3 7 1 1 0 0 C
4 8 3 8 1 1 0 1 D
4 8 4 7 1 1 1 0 E
4 8 4 8 1 1 1 1 F
Now, how easy would it be to memorize?:
My combination is 9
9 is 1 0 0 1 (you must memorize the binary digits for the hexadecimal values)
9 is 4 7 3 8