
Mae D.
asked 04/09/18Organic Chem
A sample of neon gas occupies a volume of 7.22 L at 53.0°C and 1.21 atm.
If it is desired to decrease the volume of the gas sample to 5.13 L, while increasing its pressure to 1.52 atm, the temperature of the gas sample at the new volume and pressure must be
If it is desired to decrease the volume of the gas sample to 5.13 L, while increasing its pressure to 1.52 atm, the temperature of the gas sample at the new volume and pressure must be
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1 Expert Answer

David J. answered 09/19/20
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Highly experienced and effective PhD organic chemistry tutor
PV = nRT
Assuming constant "n"...
PV = CT C = nR
PV/T = C
(1.21 atm)(7.22L)/(273.15 + 53) = C = 0.0268
T = PV/C = (1.52 atm)(5.13 L)/0.0268 = 291 K (18 degs C)
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Arturo O.
04/09/18