
Bobosharif S. answered 03/26/18
Tutor
4.4
(32)
Mathematics/Statistics Tutor
3x+2y=13
xy=2
From the second equation y=2/x, (x≠0) and substitute into the first one
3x+2(2/x)=13
3x2-13x+4=0
x=1/3, x=4
y=2/(1/3)=6, and y=1/4
So, there two pairs of solutions: (1/3, 6) and (4, 1/4).