
Andy C. answered 03/04/18
Tutor
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Math/Physics Tutor
The slope of XY is M = (2 - -3)/(6 - -2) = 5/8
Using Y(6,2), the equation of route XY has intercept B = y - mx = 2 - (5/8)(6) = 2 - 30/8 = 16/8 - 30/8 = -14/8 = -7/4
So the equation of route XY is y = (5/8)X - 7/4
The line perpendicular to XY must have slope -8/5 and pass through Z.
THerefore, the line perpendicular to route XY has intercept B = y - mX = 2 - (-8/5)(1) = 2 + 8/5 = 10/5+8/5 = 18/5
So the line perpendicular to route XY is y = (-8/5)x + 18/5
They intersect at :
(5/8)x - 7/4 = (-8/5)x + 18/5
Multiplying everything by common denominator 40:
25x - 70 = -64X + 144
25 x - 70 + 64x - 144 = 0 <---- everything to left side
89x - 214 = 0
x = 214/89
THen y = (5/8)(214/89) - 7/4
= 1070/712 - 7/4
= 1070/712 - 1246/712 <--- common denominator
= -176/712
= -88/356
= -44/178
= -22/89
and
y = (-8/5)(214/89) + 18/5
= -1712/445 + 18/5
= -1712/445 + 1602/445
= -110/445
= -22/89
So the road from the patrol tower at Z to the main route XY intersect at (214/89, -22/89)
THe distance from the patrol tower at Z to the main route XY is
the distance between Z(1,2) and ( 214/89, -22/89)
OR
sqrt ( (2 - (-22/89))^2 + (1 - 214/89)^2 ) =
sqrt ( ( 178+ 22)/89 )^2 + (( 89 - 214)/89))^2 ) =
sqrt ( (200/89)^2 + ( -125/89)^2 ) =
1/89 * sqrt ( 200^2 + (-125)^2 ) <---- 1/89 factors out of the denominator
1/89 * sqrt ( 40000 + 15625) =
1/89 * sqrt ( 55625) =
1/89 * sqrt ( 125 * 445 ) =
1/89 * sqrt ( 5 * 5 *5 * 5 *89) =
1/89 * 25 * sqrt(89)
or approximately = 2.65