Write the balanced equation for the reaction between potassium hydroxide and sulfuric acid?

Question

If 25g of sulfsulf acid is reacted 7.7g of potassium hydroxide, how many grams of potassium sulfate are prproduc? 

Answer 1

2KOH + H2SO4 = K2SO4 + 2H2O <-balanced eq. 

25gx1mol/98g=0.255 mol H2SO4

7.7gx1mol/56g=0.138 mol KOH

KOH is limiting 

moles K2SO4 = 0.138/2 = 0.069

mass K2SO4 = 0.069 mol x 174g/mol = 12 g