Phantom L.

asked • 02/19/18

Find the solution for the following exact differential equations.

3y3e3xy - 1 + (2ye3xy + 3xy2e3xy)y' = 0

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Bobosharif S. answered • 02/22/18

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3y3e3xy - 1 + (2ye3xy + 3xy2e3xy)y' = 0
(3y3e3xy - 1)dx + (ye3xy (2+ 3xy)dy = 0
y2e3xy - x=C (general solution)
If any questions, let me know
 
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M H.

could you show you you found the general solution by integrating N with respect to y to get F ( x,y ) with steps please?
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05/09/22

M H.

Because the general solution is easier to find by integrating M with respect to x but I cannot configure out by integrating N and adding up the steps of solving for h(x)
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05/09/22

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