If x varies directly as y and x =12 when y=8, then what is the value of x when y=12?

Question

If x varies directly as y and x =12 when y=8, then what is the value of x when y=12?

Answer 1

y = kx

8 = 12k

(2/3) = k

 

12 = (2/3)x

 

Can you solve for x and answer?

Answer 2

y = k*X where k is a fixed number constant

 

8 = k*12

 

k = 8/12 = 2/3

 

y = (2/3)x

 

12 = (2/3)x

 

x = 12*3/2 = 36/2 = 18