ABDULLAH W.
asked 02/03/18
show that if a square matrix A satisfies the equation
A2 + 5A -2I = 0 THEN A-1 = 0.5 (A + 5I ) .
Bobosharif S.
answered 02/03/18
Advanced User of Windows
A2 + 5A -2I = 0
A2 + 5A =2I (multiply both sides from right by A-1)
A*A*A-1+5AA-1=2I*A-1
A*I+5I=2A-1
A-1=0.5(A+5I)
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