the average of two numbers is 7, and three times the difference between them is 18. find the numbers

Question

the average of two numbers is 7, and three times the difference between them is 18. find the numbers

Answer 1

Hello,


(x + y)/2 = 7   <-----The average of two numbers is 7/
(x - y)*3 = 18   <-----Three times the difference between them is 18

Then: 

(x + y)/2 = 7
x + y = 14
y = 14 - x, substitute this into (x - y)*3 = 18.


(x - (14 - x))*3 = 18
(x - 14 + x)*3 = 18
(2x - 14)*3 = 18
2x - 14 = 6
2x = 6 + 14
2x = 20
x = 10, plug this into (x + y)/2 = 7.

Then:

(10 + y)/2 = 7
10 + y = 14
y = 4


x = 10  y = 4 

I hope I have helped and wish you a great weekend.