Eugene E. answered 12/29/17
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Let A be a square matrix and let A* denote the adjoint of A. Set A1 = (A + A*)/2 and A2 = (A - A*)/2. Note A1 + A2 = A. Since (A*)* = A, then
(A1)* = (A* + A)/2 = A1
(A2)* = (A* - A)/2 = -(A - A*)/2 = -A2
Therefore A1 is Hermitian and A2 is skew-Hermitian.
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12/29/17