How do you write an equation in standard form of the lines that passes through (6,2) and the slope:10

Question

Slope: 10, passes through (6,2)

Answer 1

Based on the information provided, you should use the Point Slope form, initially. That's very straightforward:

 

y-2 = 10(x-6).

 

Next, DISTRIBUTE. Then, do whatever is necessary to put both the x and y terms together on one side (by adding the opposite of the x term to both sides).

 

Result: something like 

Ax + By = C, with A > 0 ... Standard form.

Answer 2

Since you are given a point and a slope, use the Point-Slope Form of the equation of a line:

y - y₁ = m(x - x₁)

 y - 2 = 10(x - 6)

y - 2 = 10x - 60

10x - y - 58 = 0