integral problem

Question

solve for the integral....dx/xsqrt(9-4x^2)

Answer 1

4x^2=9(sinu)^2.......8x(dx)=18sinucosu. Multiply integral by x/x to get    xdx/x^2rad9-4x^2..substitute. So

(18/8sinucosu)over[9/4(sinu)^2rad(9(1-sin^2 u))     hope you can do the rest....comes out to involve 1/3 integral csc u. hope this was partially  helpful. pain to type in full explanation.