
Arturo O. answered 11/03/17
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Assuming that by northwest you mean 135° from east, the components of the resultant vector are
u = (6 + 13cos135°) km/hr = -3.192 km/hr
v = (0 + 13sin135º) km/hr = 9.192 km/hr
√(u2 + v2) = √[(-3.192)2 + (9.192)2] km/hr ≅ 9.73 km/hr