Inactive Tutor answered 02/10/25
Tutor
New to Wyzant
lim(nsin(7/n)) n→∞ = (n = 1/x, x →0) = lim x →0(1/xsin(7x) = lim x →0 7sin(7x)/(7x) = 7·1 = 7
Anita T.
asked 11/02/17Inactive Tutor answered 02/10/25
lim(nsin(7/n)) n→∞ = (n = 1/x, x →0) = lim x →0(1/xsin(7x) = lim x →0 7sin(7x)/(7x) = 7·1 = 7
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