A 5dm^3 vessel contains 2gm of hydrogen and 28g of nitrogen at 27C find the total pressure of mixture of gases

Question

A 5dm^3 of Vessel contains 2gm of hydrogen and 28gm of nitrogen find the total pressure of mixture of gases?

Answer 1

moles H2 = 2 g x 1 mole H2/2 g = 1 mole

moles N2 = 28 g x 1mole N2/28 g = 1 mole

PV = nRT

P = ?

V = 5 L

n = 2 moles (1 mole H2 + 1 mole N2)

R = 0.082 Latm/Kmole

T = 27 + 273 = 303K

P = nRT/V = (2)(0.0821)(303)/5 = 9.95 atm = 10 atm