Kris V. answered 09/21/17
Tutor
5
(36)
Experienced Mathematics, Physics, and Chemistry Tutor
-i/(2-5i)
= -i/(2-5i)[(2+5i)/(2+5i)] {Multiplying both numerator and denominator by the complex conjugate of 2-5i}
= -i(2+5i)/[(2-5i)/(2+5i)]
= (5-2i)/29
=(5/29) - (2/29)i