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what are the four algebraic processes and define each process with an example

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1 Answer

1. Simplify
[(x2+2x-3)]/[(x+3)(x-3)]=10+y2+2y-4y+8-2y2
The right side requires simplification in that we need to combine like terms.
[(x2+2x-3)]/[(x+3)(x-3)]=10 + y+ 2y - 4y +8 - 2y2
[(x2+2x-3)]/[(x+3)(x-3)]=(-2y2+y2)+(2y-4y)+(10+8)
[(x2+2x-3)]/[(x+3)(x-3)]= - y- 4y + 18
It is now simplified.
 
2. Factor
The numerator (x2 + 2x - 3) of the left side can be factored...
[(x+3)(x-1)]/[(x+3)(x-3)]=-y2-4y+18
[(x+3)(x-1)]/[(x+3)(x-3)]=-y2-4y+18 [The (x+3) on the numerator and the denominator cancel each other out.]
(x-1)/(x-3)=-y2-4y+18
It is now factored.
 
3. Evaluate
We can evaluate the fact that in its original form, the domain can include all integers except -3 and 3.
In its current form, the domain can include all integers except 3.
 
4. Solve
Graph the results.