
Andrew M. answered 07/11/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Let A = (-24,16)
Let B = (56, -16)
Let C = (-72, -32)
Midpoint of AB = ((56-24)/2, (-16+16)/2)) = (16,0)
Slope of segment AB:
m = (-16-16)/(56-(-24)) = -32/80 = -2/5
perpendicular slope is negative reciprocal = 5/2
equation for perpendicular bisector of AB is line through
(16,0) and slope 5/2
Using the point slope equation the equation for the perpendicular
bisector of AB is:
y - 0 = (5/2)(x-16)
y = (5/2)x - 40
2y = 5x - 80
5x - 2y = 80
Now find the midpoint of AC and BC
and their slopes in similar fashion. Using the midpoints and
negative reciprocal slopes follow the same
procedure to determine the equations of
the perpendicular bisectors of AC and BC
This will give you three simultaneous equations
to solve. The solution of this system of equations
will be the circumcenter of the system and the
answer to the problem