
Andrew M. answered 07/09/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
A(-1,6), B(2,-3)
slope = (change in y)/(change in x)
m= (-3-6)/(2-(-1)) = -9/3 = -3
Length is distance from A to B
d = √[(x2-x1)2+(y2-y1)2]
d = √[(2-(-1))2+(-3-6)2]
d = √[(3)2+(-9)2]
d = √90
d = 3√10
Midpoint = [(x1+x2)/2 , (y1+y2)/2]
= ((-1+2)/2 , (6-3)/2)
= (1/2 , 3/2)
Perpendicular lines have negative reciprocal
slopes... m⊥ = -1/m
m⊥ = -1/-3 = 1/3
Equation of line with slope 1/3 through (4,7)
y -y1 = m(x-x1)
y - 7 = (1/3)(x-4)
3y - 21 = x-4
-x + 3y = 17 or x - 3y = -17