What is the y-intercept and x-intercept for y=x^2-4x

Question

I need to know the y-intercept and x-intercept and the vertex 

Answer 1

For any quadratic function, your vertex is -b/2a

In this case, it's x=2

 

By factoring, you can determine the x-intercepts: y=x²-4x = x(x-4)

Your x-intercepts are the values where y=0, thus, the points (0,0) and (4,0) are the intercepts.

 

Your y-intercept is the point where x=0, thus (0,0) is your y-intercept.