The equation you have is a Linear Equation, meaning that it will produce a line on a coordinate graph. So in order to solve it you need to either create a table of values that make it true like you have tried or find the slope and the y-intercept and then graph it to find solutions. I would do the second option but it depends on your instructions and what you have learned so far.
To find the slope I would manipulate the equation until it is in the Slope-Intercept form y = mx + b, where "m" is the slope and the "b" is the y-intercept, (0,b).
1. Subtract "x" from both sides of the equation yielding -3y = 5 - x
2. Now just so that it matched the form we want, turn around the left side to yield -3y = -x + 5
3. Now divide by -3 on both sides or if you prefer you can multiply by -1/3 yielding -3/-3 y = -1/-3 x + 5/-3
4. Now simplify to yield y = 1/3 x - 5/3
So the m or slope is 1/3 and the y-intercept is at (0,-5/3 or -1 2/3)
Do you know how to graph that? If not then plot the y-intercept on the y-axis at - 1 2/3 and then move down 1 unit (because it is negative) and 3 units to the right (from the slope - do you need slope explained?). Plot a point there and draw the line. The line is the solution to this equation but if you need actual points - (x,y) then find points on the graph where it is easy to determine the coordinates of the point and list them in a table of values. Do you know how to do that?
Vicky, are you supposed to find the x- and y- intercepts? If so, you set y = to zero for the x-intercept which looks like this:
x -3(0) = 5
x-0 = 5
So the x-intercept is at (5,0)
To find the y-intercept, set x = to zero:
0 - 3y = 5
-3y = 5
then divide both sides by -3
(-3)/(-3) y = 5/(-3)
y = 5/(-3)
y = -5/3 or - 1 2/3
So the y-intercept is (0, -1 2/3)
Is this what you need?