Michael J. answered 07/07/17
Tutor
5
(5)
Effective High School STEM Tutor & CUNY Math Peer Leader
∫(arcsinx)(1 + x)-1/2dx
u = arcsinx dv = (1 + x)-1/2dx
du = 1 / √(1 - x2)dx v = 2(1 + x)1/2
Then the integral is
2(1 + x)1/2arcsinx - 2∫√((1 + x) / (1 - x2))dx
2(1 + x)1/2 arcsinx - 2∫(1 - x)-1/2 dx
You can finish up here by taking care of the sub-integral using substitution.