Let the we denote the distance traveled by d,
average speed of the car vc,
and the average speed of the bus vb.
We use the relationship
distance = speed (times) time
for the bus and the car.
d = 30/60 • vc (1)
d = 45/60 • vb (2)
We also know the relationship between the two average speeds vc and vb:
vb = vc -12. (3)
We will substitute the value of bus speed in (2) and then we subtract equation (2) from equation (1):
d =45/60 • (vc-12)
-
d =30/60 • vc
0 = 45/60 vc -45/60 •12 -30/60 vc
15/60 vc - 9=0.
We solve that equation and find vc (calculation omitted):
vc = 36.
Next, we use the equation (1) to find the distance:
d = 30/60 • 36 m/h
d =18 miles.
Questions?
For your understanding, you may change the numbers and try to write and solve the problem again.