HELLPPPP!!!! Jun 13 | EFRGEQRTG from Saint Ann, MO | 3 Answers | 0 Votes Mark favorite Subscribe Comment
Assuming (3x^{2} + 5) + ( 16x^{2} + 7) = (3x^{2} + 16x^{2} + 5 + 7 ) = 19x^{2} + 12 Bill. Jun 13 | Bill M. Comment
Do everything inside the () first. Remember that multiplication comes before addition. Do the two multiplications. So you get... (6+5)+(32+7) 11+39=50 Jun 13 | Brian H. Comment
I assume the same as Bill, with the 2's being exponents, in which case you'd add your like terms. The x^{2} terms can be added (no change in power there!) and the constants can be added. Jun 13 | Darlene N. Comment