HELLPPPP!!!!

Assuming (3x

^{2}+ 5) + ( 16x^{2}+ 7) = (3x^{2}+ 16x^{2}+ 5 + 7 ) = 19x^{2}+ 12Bill.

HELLPPPP!!!!

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Overland Park, KS

Assuming (3x^{2} + 5) + ( 16x^{2} + 7) = (3x^{2} + 16x^{2} + 5 + 7 ) = 19x^{2} + 12

Bill.

Santee, CA

Do everything inside the () first. Remember that multiplication comes before addition. Do the two multiplications. So you get...

(6+5)+(32+7)

11+39=50

Georgetown, KY

I assume the same as Bill, with the 2's being exponents, in which case you'd add your like terms. The x^{2} terms can be added (no change in power there!) and the constants can be added.

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