what is the result of the integral of the following,the letter is q

Question

∫   -2 dq             
(cos-1q)√(1-q2)

Answer 1

Am I correct in interpreting the (cos-1q) to be cos(-1q) ?

Is the integral only that part above the line?
[ ∫-2 dq] / ((cos(-1q)) (√(1-2q))

 

Then --

( ∫ -2 dq)/(cos(-q) √(1-2 q)) = -(2 q sec(q))/√(1-2 q)

 

Other forms of the answer are:

(2 √(1-2 q) q)/(2 q cos(q)-cos(q))

-or-

-(4 q)/((e^(-i q)+e^(i q)) √(1-2 q))

BUT - If the integral is meant to be the whole thing ∫-(2/((cos(-1q))√(1-2q)))dq

That is a tougher problem.
The result is:

-2 ∫ [ √(1 - 2 q) Sec(q) dq]

Even Mathematica could not reduce it any further.