Jennifer N. answered 05/23/17
Tutor
New to Wyzant
Engineering Student specializes in math subjects
u=2+x3
(1/3)du=x2
(1/3)∫(1/u1/3)du
*rewritten as*
(1/3)∫u-1/3du
(1/3)(3/2)u2/3+C
(1/2)(2+x^3)2/3+C

Michael A.
05/23/17