Search
Ask a question
0

Find general solution of y" + 2y' + y = 2e^-t

Answer: c1e^-t + c2t^-t + t^2e^-t

1 Answer by Expert Tutors

Tutors, sign in to answer this question.
Deanna L. | Electrical engineering major and music lover with MIT degreeElectrical engineering major and music l...
4.9 4.9 (123 lesson ratings) (123)
0
This is second order diff equatin which means if you break it down in the form of ay'' + by' + cy  you get general solutions of -b/2a or -1. (the b^2-4ac terms disappear from the quadratic formula). That means that by definition the general solution is C1e^-t + c2te^-t. The double integral of 2e^-t is t^2e^-t (first integral is 2te^-t).
 
Add those terms together for the total solution. Hope that helps!
 
Deanna