-6-2(3x-18)=18

Question

i need math help  whats the process

Answer 1

Hello, thank you for taking the time to post your question!

You want to follow the order of operations in order to simplify this one down! So the first step would be distributing the -2

-6 – 2(3x – 18) = 18

-6 – 6x + 36 = 18

Then I would combine like terms

-6x + 30 = 18

-6x = -12

Then divide both sides by -6 to get the “x” variable by itself

x = -12/-6 = 2

I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

- 6 - 2(3x - 18) = 18

 

Using BODMAS

 

B - Bracket

O - Order of

D - Division

M - Multiplication

A - Addition

S - Subtraction

 

we'll have to solve the brackets first.

 

- 6 - 2(3x - 18) = 18

 

- 6 - 6x + 36 = 18

 

Now we'll solve for like terms

 

-6x = 18 +6 - 36

 

-6x = 24 -36

 

-6x = -12

 

divide both sides by -6

 

x = -12/-6

 

x = 2

 

 

Check

-6 -2(3x - 18) =18

sub 2 for x

-6 -2(3(2) - 18) = 18

-6 -2(6 - 18) = 18

-6 -12 + 36 = 18

-18 + 36 = 18

18 = 18