The rectangle has a perimeter of 66cm and area is 216cm^(2), Its length is 6 more than twice its width.

Question

Please solve as soon as possible

Answer 1

Hello Missybelle. 

 

Is means =

6 more than means +6

twice means 2 times

 

So we have L=2w+6.

 

To find perimeter, it means to find the outside of the rectangle. A rectangle has 2 lengths and 2 widths so you would have L+L+W+W=66. However, we just said that L=2W+6, we would plug it in as L. Then we have,

 

(2W+6)+(2W+6)+W+W=66

 

After you add the like terms, you can solve for W. And then you would plug in your answer for W to L=2W+6 to solve for L.

 

 

 

Answer 2

A=l*w

w=width

2w+6=length

216=(2w+6)(w)

216=2w^2+6w

2w^2+6w-216=0

divide both sides by 2

w^2+3w-108=0

108=2*2*3*3*3=(2*2*3)*(3*3)=12*9 and 12-9=3

(w+12)(w-9)=0

w-9=0

w=9

width=9 cm

length=2*9+6=24 cm

2*9+2*24=18+48=66 and 9*24=216

Answer 3

Hy missybelle,

 

Perimeter of a rectangle = 2L + 2W

 

 

Area of  a rectangle = length * width

 

 

length of the rectangle = 2w + 6

 

 

2(2w+6) + 2w = 66

 

4w + 2w = 54

 

6w = 54

 

w = 9cm

 

9L = 216

 

L = 24cm

 

 

The length of the rectangle is 24 cm and its width is 9 cm. Good luck with the rest of your problems.

 

 

regards,

 

mayuran