A team played 62 games. They won 32 more games than they lost. How many games did they win?

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Shelly J. | Excellent Maths Tutoring for academic successExcellent Maths Tutoring for academic su...

Hi Mary,

A team played 62 games.

Let the number of games they lost=x

They won 32 more games than they lost

Number of games they won =32+x

Number of games lost+number of games won=Total number of games

x+32+x=62

2x=62-32

2x=30

2x/2=30/2

x=15

Number of games they lost=15

Number of games they won =32+x=32+15=47

Total number of games played = 62

Let x = the unknown number of games won

From the problem, we know that the team won 32 more games than they lost. The number of games they lost = x - 32 They lost 32 fewer games than they won

Now we know that the number of games won + the number of games lost = 62

x + (x -32) = 62

2x - 32 = 62

Now solve for x, the number of games won. Let me know what you get!

2x - 32 = 62

To find x:

- Add 32 to both sides
- Then divide both sides by 2

Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...

It would be same if it was said that Peggy and Sally together spent 62 dollars on shopping mall , if Sally spent 32 dollars more how much each spent.

The key to word problem is choose a variable , X , for the unknown what the problem is asking you to find out, and convert the word problem to algebraic statement in terms of the variable chosen and solve.

X - amount of money Sally spent, or games lost

X + 32 - amount of money peggy spent ,or game won.

X + X + 32 = 62

Solve for X.

This is an example of math talks about relationship between 2 objects regardless of the nature of the objects.

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