
Kurt T. answered 02/26/17
Tutor
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Math Tutoring and Test Prep
Think about it. There is one way (1234) to choose four out of four, four ways (123, 124, 134, 234) to choose three out of four, six ways (12, 13, 14, 23, 24, 34) to choose two out of four, and four ways (1, 2, 3, 4) to choose one out of four. Fifteen possible combinations in all.
You can also use factorials to answer this question without listing out the possible combinations. If n is the total number and x is the number chosen, then...
You can also use factorials to answer this question without listing out the possible combinations. If n is the total number and x is the number chosen, then...
nCx = n! / (x! (n-x)!)
4C4 = 4! / (4! 0!) = 1. Remember that 0! = 1.
4C3 = 4! / (3! 1!) = 4.
4C2 = 4! / (2! 2!) = 6.
4C1 = 4! / (1! 3!) = 4.
1 + 4 + 6 + 4 = 15.
The remaining possibility - choosing zero out of four - can be disregarded if you must choose at least one of the four answers.