
Michael C. answered 02/06/17
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Let the speed of car be c mph
Then speed of aircraft = 2c - 6
time = distance/average speed
time taken by car = 153/c
time taken by aircraft = 288/(2c-6)
since both times are equal then, 153/c = 288/(2c-6)
cross multiply; 153(2c-6) = 288c
306c - 918 = 288c; expanding
306c - 288c = 918; collecting like terms
18c = 918; dividing by 18 on both sides
c = 918/18 = 51 mph = speed of car
therefore speed of aircraft - 2c-6 = 2*51 - 6 = 96 mph
checking; 153/51 = 288/96 = 3 hours