How do you graph 2x^2+x-14?

Question

I have to graph Parabolas for my algebra class and I totally forgot. Help Please!!!

Answer 1

Hi La;

f(x)=2x²+x-14

The parabola opens upward.  We know that because the coefficient of x² is positive.

We need to know where the vertex is...

Vertex is -b/2a

-1/[(2)(2)]

-1/4

x=-1/4

Let's establish the value of y...

y=2x²+x-14

y=[(2)(-1/4)²]+(-1/4)-14

y=[(2)(1/16)]-(1/4)-14

y=(1/8)-(1/4)-14

y=(1/8)-(2/8)-14

y=(-1/8)-14

y=-14 1/8

vertex is (-1/4, -14 1/8)