Roman C. answered 01/31/17
Tutor
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(852)
Masters of Education Graduate with Mathematics Expertise
Let the terms be 2,2x,2x2,…,2xn-1.
Then we have the following system:
1. 2xn-1 = 2048
2. 2(xn - 1)/(x - 1) = 2730
The first equation becomes xn = 1024x.
Substitute that in the second equation and solve for x:
2(1024x - 1)/(x - 1) = 2730
1024x - 1 = 1365(x - 1)
1024x - 1 = 1365x - 1365
1364 = 341x
4 = x
Finally, plug this in and find n.
4n = 4096
n = 6
So the sequence is 2,8,32,128,512,2048 with 6 terms and common ratio 4.