find the equation of the line passing through (4,5) and :

Question

perpendicullar to the line 13x - 6y - 11 = 0

Answer 1

I like putting answers in point slope form.

 

y - y₁ = m(x - x₁)

 

Our point (4 , 5) = (x₁ , y₁₎

 

We fill these values in and our point slope form is:

 

y - 5 = m(x - 4)

 

All we need now is the slope.

 

Perpendicular line's slopes are negative reciprocals of each other.

 

Let's find the slope of 13x - 6y -11 = 0 by solving for y

 

- 6y = -13x + 11

 

y = 13/6x -11/6   (The slope of the line given is 13/6)

 

Therefore, the slope you need is -6/13

 

ANSWER:  y - 5 = -6/13(x - 4)