Akasapu K.

asked • 01/13/17

Help me out with this problem

If the four letter words(need not be meaningful) are to be formed using the letters from the word, "MEDITERRANEAN" such that the first letter is "R" and the fourth letter is "E", then the total number of all such words is?
 
a. 110
b. 59
c. 56
d. (11!)/(2!)^3

1 Expert Answer

By:

Jason L. answered • 01/13/17

Tutor
4.8 (6)

Graduate Student Who Loves to Do Math

Amos J.

Hello Akasapu,
 
I think we may need to extend Jason's reasoning in the final paragraph of his answer to include repeated letter occurrences for the middle two spots of our four-letter word combination. Your answer should end up being smaller than 110.
 
If we parse the letters in the word MEDITERRANEAN for multiple occurrences of each letter, we'll find that we have:
 
     3(E), 2(A, N, R), and 1(D, I, M, T).
 
 
One of the Rs will be fixed into the first spot of our four-letter word combination, and one of the Es will be fixed into the last spot, so for the middle two spots we are left with:
 
     2(A, E, N) and 1(D, I, M, R, T)
 
We'll need to consider two distinct cases here: 1) if one of the double letters (A, E, or N) are selected for the 2nd spot in our four-letter word combination, and 2) if one of the singles (D, I, M, R, or T) are selected for the 2nd spot. If we add all combinations from both cases, we should arrive at the total number of unique four-letter words we can assemble.
 
In the first case, we can select one out of three letters for the 2nd spot, followed by any of the remaining eight letters for the 3rd spot. So, for case 1), we have 3(8) = 24 possible combinations. However, there are three duplicate combinations in this calculation, in the three cases RAAE, REEE, and RNNE. So, we end up with 21 unique word combinations that arise from case 1).
 
In the second case, we can select one out of five letters for the 2nd spot, followed by only 7 remaining letters for the 3rd spot. So, for case 2), we have 5(7) = 35 unique word combinations.
 
In total, we ought to have 21 + 35 = 56 unique word combinations.
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01/15/17

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