One number is 2 less than a number. Twice the second number is 11 less than 5 times the first. Find the two numbers

Question

One number is 2 less than a number. Twice the second number is 11 less than 5 times the first. Find the two numbers

Answer 1

I think your wording of your question is a bit off... but here we go

 

Let A = first number

Let B = second number

 

A = B-2

 

2B = 5A-11

 

Solve by substitution

 

2B = 5(B-2)-11

 

2B = 5B-10-11

 

-3B = - 21

 

B = 7

 

A = B - 2 --> A = 7 - 2 =5

 

A = 5

B = 7

Answer 2

n represents a number

n - 2 represents the other number

Twice  second  is   11 less  5   times first

2        (n - 2)   =     -11    +  5     (n)

2(n - 2) = -11 + 5n

 

Can you solve for n and answer the question?