Jared V.

asked • 12/09/16# Indefinite integral of tan^8x

After taking the integral I have (1/7)tan^7x+C-(1/5)tan^5x-C. I got this by breaking a tan^2x off and converting it into sec^2x-1. My question is what happens to my C when I have C-C?

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## 1 Expert Answer

Shree S. answered • 12/09/16

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Mark M.

12/09/16