
Harris C.
asked 12/06/16If f' is continuous on [a,b], show that
2∫ab f(x)f'(x)dx=[f(b)]2-[f(a)]2
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1 Expert Answer

Kenneth S. answered 12/06/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
If f' is continuous on [a,b], show that:
2∫a b f(x) f'(x) dx = [f(b)]2 - [f(a)]2
3 hours ago | Jay from Oakland, CA |
Integral Calculus, Calculus
.........................................................
Answer: Note that by the Chain Rule:
d/dx f2(x) = 2f(x)f'(x)
Thus the identity
2∫ab f(x) f'(x) dx =f2(b) - f2(a).
...........................................................
THIS IS A CUT-AND-PASTE of answer (by another tutor) sent to same question yesterday.
2∫a b f(x) f'(x) dx = [f(b)]2 - [f(a)]2
3 hours ago | Jay from Oakland, CA |
Integral Calculus, Calculus
.........................................................
Answer: Note that by the Chain Rule:
d/dx f2(x) = 2f(x)f'(x)
Thus the identity
2∫ab f(x) f'(x) dx =f2(b) - f2(a).
...........................................................
THIS IS A CUT-AND-PASTE of answer (by another tutor) sent to same question yesterday.
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Kenneth S.
12/06/16