Kenneth S. answered • 12/01/16
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If all 26 letters & all ten digits are available, then there are various possibilities indicated by the following patterns, using L for letter, x for anything else.
Lxx xLx xxL.
Let's choose the components for the Lxx structure: 26 choices for first position, then 36 choices for 2nd position & 36 choices for 3rd position. This is 33696 possibilities.
If we compute the others, we get 36(26)(36) & 36(36)(26) as the number of those, so the total is 3 times said product; 3(33696) = 101,088 different licenses.
Kenneth S.
Yes, and yes (permutations). But it has to be approached carefully--that's why I segregated it into three distinct patterns.
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12/01/16
Oa A.
Thank you
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12/02/16
Oa A.
sorry but i want to ask why did we multiply 101,088 by 3 ?
didn't we already have calculated all possible probabilities for the 3 cases(letter come first ,second and last)by adding
them together or am missing something ?
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12/02/16
Oa A.
12/01/16