Write the equation of the line that goes through point (4,-3) and is perpendicular to the equation y=4/3x+2

Question

I needed help with a algebra problem

Answer 1

You have an equation in slope intercept form, y = mx + b

where m is the slope, b is y-intercept:

 

y = (4/3)x + 2 ... slope m=4/3

 

Perpendicular lines have a slope that is the negative reciprocal.

Slope of perpendicular line is m = -3/4

 

Thus, you want the equation of the line through (4,-3) with slope -3/4

 

y = (-3/4)x + b

Use the point for x,y to find b

 

-3 = (-3/4)(4) + b

-3 = -3 + b

0 = b

 

Your equation is:  y = (-3/4)x