The ionisationenergy and electron affinity of an element are 13.0eV and 3.8eV Its electronegativity??

Question

• here are the options 
• 2.8
• 3.0
• 3.5
• 4.0

please do show the steps to solve the problem too...

Answer 1

I assume you want the Mulliken electronegativity, since you provided ionization energy and electron affinity in eV. 

 

Χ_M = Mulliken electronegativity

 

E_i = ionization energy = 13.0 eV

 

E_ea = electron affinity = 3.8 eV

 

X_M =  0.187(E_i + E_ea) + 0.17, with E_i and E_ea in eV

 

Χ_M = 0.187(13.0 + 3.8) + 0.17 = 3.31

 

This is different from the given options, but the closest one is 3.5