A graph of temperature (°C) versus solubility of benzoic acid in water (g/L) has a good exponential fit, y = 1.479e0.0357x,

Question

(continued...) indicated by the Goodness of Fit R2 = 0.9955.  Don't forget that there are 1000 ml in a liter.  Round to a whole number answer without any decimal point.   Given that you used 12.4 ml of water to dissolve 0.585 g of benzoic acid, what was the actual temperature of your recrystallization setup according to this exponential equation?

 

 

This is for my o chem homework .I need to know how to do it but i'm super stuck. I'd appreciate it if someone helped. Thanks

Answer 1

Since the x value is given as g benzoic acid/L H2O, simply carry out that ratio:

 

x = (0.585 g)/(0.0124 L) = 47.18 g/L

 

Now, plug in this value of x into the function and determine y:

 

y = 1.479e^(0.0357(47.18)) = 8 degC.