Michael J. answered 09/26/16
Mastery of Limits, Derivatives, and Integration Techniques
Yes, you are correct.
For equating the equations, you get
x2 + kx - 3x + 4 = 0 eq1
Setting the derivative of f(x) equal to 3 yields
f'(x) = 3
2x + k = 3 eq2
Now we substitute the value of k from eq2 into eq1.
x2 + x(3 - 2x) - 3x + 4 = 0
Solve for x from this equation. Then plug in the value of x into eq2 to solve for k