
Arturo O. answered 09/24/16
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
Let x and y be the 2 codes, with y being the larger code.
Then the given conditions become:
y = 2x
x + y = 1407
Solve the 2 equations above by substitution:
x + 2x = 1407
3x = 1407
x = 1407/3 = 469
Then y = 2x = 2*469 = 938
The 2 codes are 469 and 938. You can test the solution.