(sin(p-x))/(p-x)

Question

Find the limit as x approaches π (pi).

Answer 1

lim_x→π[sin(π-x)/(π-x)]

 

Let θ = π-x  Then, as x→π, θ→0

 

So, the given limit is equivalent to lim_θ→0[sinθ/θ]

 

                                                 = 1