
Arturo O. answered 09/19/16
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
d = s + s2/20
d = braking distance = 125 ft
s2/20 + s - 125 = 0
0.05s2 + s - 125 = 0
s = [1 / (2*0.05)] {-1 ± √[(1)2 - 4(0.05)(-125)]} mph
s = 10 (-1 ± √26) mph
Use only the positive square root to get a positive speed.
s = 40.99 mph
We have his speed, but we were not given the speed limit, so we cannot answer whether he was telling the truth, without more information.